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2x^2=10000
We move all terms to the left:
2x^2-(10000)=0
a = 2; b = 0; c = -10000;
Δ = b2-4ac
Δ = 02-4·2·(-10000)
Δ = 80000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80000}=\sqrt{40000*2}=\sqrt{40000}*\sqrt{2}=200\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{2}}{2*2}=\frac{0-200\sqrt{2}}{4} =-\frac{200\sqrt{2}}{4} =-50\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{2}}{2*2}=\frac{0+200\sqrt{2}}{4} =\frac{200\sqrt{2}}{4} =50\sqrt{2} $
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